1214940703 has 4 divisors (see below), whose sum is σ = 1256835240. Its totient is φ = 1173046168.

The previous prime is 1214940697. The next prime is 1214940709. The reversal of 1214940703 is 3070494121.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1214940697) and next prime (1214940709).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1214940703 is a prime.

It is a super-2 number, since 2×1214940703² = 2952161823612268418, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214940709) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20947225 + ... + 20947282.

It is an arithmetic number, because the mean of its divisors is an integer number (314208810).

Almost surely, 2^1214940703 is an apocalyptic number.

1214940703 is a deficient number, since it is larger than the sum of its proper divisors (41894537).

1214940703 is an equidigital number, since it uses as much as digits as its factorization.

1214940703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41894536.

The product of its (nonzero) digits is 6048, while the sum is 31.

The square root of 1214940703 is about 34855.9995266238. Note that the first 3 decimals coincide. The cubic root of 1214940703 is about 1067.0506319615.

The spelling of 1214940703 in words is "one billion, two hundred fourteen million, nine hundred forty thousand, seven hundred three".