121521002010433 has 4 divisors (see below), whose sum is σ = 121532469512020. Its totient is φ = 121509534508848.

The previous prime is 121521002010409. The next prime is 121521002010511. The reversal of 121521002010433 is 334010200125121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 70962815667249 + 50558186343184 = 8423943^2 + 7110428^2 .

It is a cyclic number.

It is not a de Polignac number, because 121521002010433 - 2⁹ = 121521002009921 is a prime.

It is a super-2 number, since 2×121521002010433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121521002010398 and 121521002010407.

It is not an unprimeable number, because it can be changed into a prime (121521002019433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5733734898 + ... + 5733756091.

It is an arithmetic number, because the mean of its divisors is an integer number (30383117378005).

Almost surely, 2^{121521002010433} is an apocalyptic number.

It is an amenable number.

121521002010433 is a deficient number, since it is larger than the sum of its proper divisors (11467501587).

121521002010433 is a wasteful number, since it uses less digits than its factorization.

121521002010433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11467501586.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 121521002010433 its reverse (334010200125121), we get a palindrome (455531202135554).

The spelling of 121521002010433 in words is "one hundred twenty-one trillion, five hundred twenty-one billion, two million, ten thousand, four hundred thirty-three".