Base | Representation |
---|---|
bin | 10110101000110000… |
… | …01011110010110011 |
3 | 1011100222002121110012 |
4 | 23110120023302303 |
5 | 144342134403042 |
6 | 5325533525135 |
7 | 610110112406 |
oct | 132430136263 |
9 | 34328077405 |
10 | 12153044147 |
11 | 5177092a42 |
12 | 24320437ab |
13 | 11b8a8b1aa |
14 | 834099d3d |
15 | 4b1e01e82 |
hex | 2d460bcb3 |
12153044147 has 8 divisors (see below), whose sum is σ = 12251676672. Its totient is φ = 12054457800.
The previous prime is 12153044143. The next prime is 12153044191. The reversal of 12153044147 is 74144035121.
12153044147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12153044147 - 22 = 12153044143 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12153044143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 686072 + ... + 703562.
It is an arithmetic number, because the mean of its divisors is an integer number (1531459584).
Almost surely, 212153044147 is an apocalyptic number.
12153044147 is a deficient number, since it is larger than the sum of its proper divisors (98632525).
12153044147 is a wasteful number, since it uses less digits than its factorization.
12153044147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23089.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 12153044147 its reverse (74144035121), we get a palindrome (86297079268).
The spelling of 12153044147 in words is "twelve billion, one hundred fifty-three million, forty-four thousand, one hundred forty-seven".
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