1215413034133 has 4 divisors (see below), whose sum is σ = 1226772034560. Its totient is φ = 1204054033708.

The previous prime is 1215413034127. The next prime is 1215413034181. The reversal of 1215413034133 is 3314303145121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1215413034133 - 2²¹ = 1215410936981 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1215413034095 and 1215413034104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1215413034193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5679500053 + ... + 5679500266.

It is an arithmetic number, because the mean of its divisors is an integer number (306693008640).

Almost surely, 2^{1215413034133} is an apocalyptic number.

It is an amenable number.

1215413034133 is a deficient number, since it is larger than the sum of its proper divisors (11359000427).

1215413034133 is a wasteful number, since it uses less digits than its factorization.

1215413034133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11359000426.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1215413034133 its reverse (3314303145121), we get a palindrome (4529716179254).

The spelling of 1215413034133 in words is "one trillion, two hundred fifteen billion, four hundred thirteen million, thirty-four thousand, one hundred thirty-three".