Base | Representation |
---|---|
bin | 10001101100000100100… |
… | …011010001101111011111 |
3 | 11022012112220201201022220 |
4 | 101230010203101233133 |
5 | 124403422314220333 |
6 | 2330230020040423 |
7 | 153551341245246 |
oct | 21540443215737 |
9 | 4265486651286 |
10 | 1215552101343 |
11 | 429570521008 |
12 | 1776b9b33113 |
13 | 8a81a62b838 |
14 | 42b93bc795d |
15 | 2194520a8b3 |
hex | 11b048d1bdf |
1215552101343 has 8 divisors (see below), whose sum is σ = 1622436806448. Its totient is φ = 809517731904.
The previous prime is 1215552101341. The next prime is 1215552101399. The reversal of 1215552101343 is 3431012555121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1215552101343 - 21 = 1215552101341 is a prime.
It is a super-2 number, since 2×12155521013432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1215552101341) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 212580580 + ... + 212586297.
It is an arithmetic number, because the mean of its divisors is an integer number (202804600806).
Almost surely, 21215552101343 is an apocalyptic number.
1215552101343 is a deficient number, since it is larger than the sum of its proper divisors (406884705105).
1215552101343 is an equidigital number, since it uses as much as digits as its factorization.
1215552101343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 425167833.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 1215552101343 its reverse (3431012555121), we get a palindrome (4646564656464).
The spelling of 1215552101343 in words is "one trillion, two hundred fifteen billion, five hundred fifty-two million, one hundred one thousand, three hundred forty-three".
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