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121624332642421 = 717374904663203
BaseRepresentation
bin11011101001110111011111…
…001001001010100001110101
3120221122011122212012211020021
4123221313133021022201311
5111420143113124024141
61110401240322405141
734422032225633530
oct3351673711124165
9527564585184207
10121624332642421
1135831654045034
121178373ab007b1
1352b318253877b
142206913225a17
15e0dadc0366d1
hex6e9ddf24a875

121624332642421 has 4 divisors (see below), whose sum is σ = 138999237305632. Its totient is φ = 104249427979212.

The previous prime is 121624332642413. The next prime is 121624332642451. The reversal of 121624332642421 is 124246233426121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121624332642421 - 23 = 121624332642413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121624332642451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8687452331595 + ... + 8687452331608.

It is an arithmetic number, because the mean of its divisors is an integer number (34749809326408).

Almost surely, 2121624332642421 is an apocalyptic number.

It is an amenable number.

121624332642421 is a deficient number, since it is larger than the sum of its proper divisors (17374904663211).

121624332642421 is an equidigital number, since it uses as much as digits as its factorization.

121624332642421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17374904663210.

The product of its digits is 663552, while the sum is 43.

The spelling of 121624332642421 in words is "one hundred twenty-one trillion, six hundred twenty-four billion, three hundred thirty-two million, six hundred forty-two thousand, four hundred twenty-one".

Divisors: 1 7 17374904663203 121624332642421