Base | Representation |
---|---|
bin | 1011000100011100100101… |
… | …1110101011111001110011 |
3 | 1121002112112111022001210012 |
4 | 2301013021132223321303 |
5 | 3043402223242123011 |
6 | 41515142434125135 |
7 | 2364220200155663 |
oct | 261071136537163 |
9 | 47075474261705 |
10 | 12171022614131 |
11 | 3972779a71117 |
12 | 14469aaa207ab |
13 | 6a3951471094 |
14 | 30111b3ac1a3 |
15 | 1618e2417a8b |
hex | b11c97abe73 |
12171022614131 has 4 divisors (see below), whose sum is σ = 12171081786672. Its totient is φ = 12170963441592.
The previous prime is 12171022614089. The next prime is 12171022614133. The reversal of 12171022614131 is 13141622017121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12171022614131 - 234 = 12153842744947 is a prime.
It is a super-2 number, since 2×121710226141312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12171022614133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29276660 + ... + 29689473.
It is an arithmetic number, because the mean of its divisors is an integer number (3042770446668).
Almost surely, 212171022614131 is an apocalyptic number.
12171022614131 is a deficient number, since it is larger than the sum of its proper divisors (59172541).
12171022614131 is an equidigital number, since it uses as much as digits as its factorization.
12171022614131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59172540.
The product of its (nonzero) digits is 4032, while the sum is 32.
The spelling of 12171022614131 in words is "twelve trillion, one hundred seventy-one billion, twenty-two million, six hundred fourteen thousand, one hundred thirty-one".
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