12173904413 has 4 divisors (see below), whose sum is σ = 13280623008. Its totient is φ = 11067185820.

The previous prime is 12173904373. The next prime is 12173904419. The reversal of 12173904413 is 31440937121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31440937121 = 11 ⋅2858267011.

It is a cyclic number.

It is not a de Polignac number, because 12173904413 - 2¹² = 12173900317 is a prime.

It is a super-3 number, since 3×12173904413³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12173904419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 553359281 + ... + 553359302.

It is an arithmetic number, because the mean of its divisors is an integer number (3320155752).

Almost surely, 2^12173904413 is an apocalyptic number.

It is an amenable number.

12173904413 is a deficient number, since it is larger than the sum of its proper divisors (1106718595).

12173904413 is a wasteful number, since it uses less digits than its factorization.

12173904413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1106718594.

The product of its (nonzero) digits is 18144, while the sum is 35.

The spelling of 12173904413 in words is "twelve billion, one hundred seventy-three million, nine hundred four thousand, four hundred thirteen".