Base | Representation |
---|---|
bin | 1011000110001101000011… |
… | …0110101100101001001001 |
3 | 1121012102110101022001212121 |
4 | 2301203100312230221021 |
5 | 3044401040021321301 |
6 | 41541054202411241 |
7 | 2366336246221135 |
oct | 261432066545111 |
9 | 47172411261777 |
10 | 12201211120201 |
11 | 3984560657594 |
12 | 1450814b00b21 |
13 | 6a67528c791c |
14 | 3027828863c5 |
15 | 1625ac87a3a1 |
hex | b18d0daca49 |
12201211120201 has 4 divisors (see below), whose sum is σ = 12201224116752. Its totient is φ = 12201198123652.
The previous prime is 12201211120193. The next prime is 12201211120223. The reversal of 12201211120201 is 10202111210221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12201211120201 - 23 = 12201211120193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12201211120271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4970311 + ... + 7007596.
It is an arithmetic number, because the mean of its divisors is an integer number (3050306029188).
Almost surely, 212201211120201 is an apocalyptic number.
It is an amenable number.
12201211120201 is a deficient number, since it is larger than the sum of its proper divisors (12996551).
12201211120201 is a wasteful number, since it uses less digits than its factorization.
12201211120201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12996550.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 12201211120201 its reverse (10202111210221), we get a palindrome (22403322330422).
The spelling of 12201211120201 in words is "twelve trillion, two hundred one billion, two hundred eleven million, one hundred twenty thousand, two hundred one".
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