12201411042341 has 4 divisors (see below), whose sum is σ = 12201437450412. Its totient is φ = 12201384634272.

The previous prime is 12201411042329. The next prime is 12201411042343. The reversal of 12201411042341 is 14324011410221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9634753920100 + 2566657122241 = 3103990^2 + 1602079^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12201411042341 is a prime.

It is a super-3 number, since 3×12201411042341³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12201411042341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12201411042343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12498416 + ... + 13439241.

It is an arithmetic number, because the mean of its divisors is an integer number (3050359362603).

Almost surely, 2^{12201411042341} is an apocalyptic number.

It is an amenable number.

12201411042341 is a deficient number, since it is larger than the sum of its proper divisors (26408071).

12201411042341 is an equidigital number, since it uses as much as digits as its factorization.

12201411042341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26408070.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 12201411042341 its reverse (14324011410221), we get a palindrome (26525422452562).

The spelling of 12201411042341 in words is "twelve trillion, two hundred one billion, four hundred eleven million, forty-two thousand, three hundred forty-one".