Base | Representation |
---|---|
bin | 10001110000010110000… |
… | …101101011101011001111 |
3 | 11022122101202010011222111 |
4 | 101300112011223223033 |
5 | 124442322133103211 |
6 | 2332305234324451 |
7 | 154103144634364 |
oct | 21602605535317 |
9 | 4278352104874 |
10 | 1220141300431 |
11 | 430505a56229 |
12 | 17857aa29727 |
13 | 8b09c336861 |
14 | 430ab4b246b |
15 | 21b13068421 |
hex | 11c1616bacf |
1220141300431 has 4 divisors (see below), whose sum is σ = 1220143747032. Its totient is φ = 1220138853832.
The previous prime is 1220141300419. The next prime is 1220141300437. The reversal of 1220141300431 is 1340031410221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1220141300431 - 29 = 1220141299919 is a prime.
It is a super-2 number, since 2×12201413004312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1220141300437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176845 + ... + 1572118.
It is an arithmetic number, because the mean of its divisors is an integer number (305035936758).
Almost surely, 21220141300431 is an apocalyptic number.
1220141300431 is a deficient number, since it is larger than the sum of its proper divisors (2446601).
1220141300431 is an equidigital number, since it uses as much as digits as its factorization.
1220141300431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2446600.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 1220141300431 its reverse (1340031410221), we get a palindrome (2560172710652).
The spelling of 1220141300431 in words is "one trillion, two hundred twenty billion, one hundred forty-one million, three hundred thousand, four hundred thirty-one".
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