Base | Representation |
---|---|
bin | 111000110100010011… |
… | …1000000110000000001 |
3 | 102122221101010121010121 |
4 | 1301220213000300001 |
5 | 3444341110011231 |
6 | 132015202300241 |
7 | 11546424042613 |
oct | 1615047006001 |
9 | 378841117117 |
10 | 122014141441 |
11 | 47822890425 |
12 | 1b792357681 |
13 | b67657333a |
14 | 5c96a42db3 |
15 | 3291c0d311 |
hex | 1c689c0c01 |
122014141441 has 4 divisors (see below), whose sum is σ = 122148667312. Its totient is φ = 121879615572.
The previous prime is 122014141399. The next prime is 122014141541. The reversal of 122014141441 is 144141410221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 122014141441 - 217 = 122014010369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122014141541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67261575 + ... + 67263388.
It is an arithmetic number, because the mean of its divisors is an integer number (30537166828).
Almost surely, 2122014141441 is an apocalyptic number.
It is an amenable number.
122014141441 is a deficient number, since it is larger than the sum of its proper divisors (134525871).
122014141441 is an equidigital number, since it uses as much as digits as its factorization.
122014141441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 134525870.
The product of its (nonzero) digits is 1024, while the sum is 25.
Adding to 122014141441 its reverse (144141410221), we get a palindrome (266155551662).
The spelling of 122014141441 in words is "one hundred twenty-two billion, fourteen million, one hundred forty-one thousand, four hundred forty-one".
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