Base | Representation |
---|---|
bin | 1011000110001101110101… |
… | …1001011001101110001111 |
3 | 1121012110000001020201112001 |
4 | 2301203131121121232033 |
5 | 3044402002403404320 |
6 | 41541131120453131 |
7 | 2366344412622442 |
oct | 261433531315617 |
9 | 47173001221461 |
10 | 12201421544335 |
11 | 398465940a331 |
12 | 145087347a1a7 |
13 | 6a678739184a |
14 | 3027a27bd659 |
15 | 1625c109320a |
hex | b18dd659b8f |
12201421544335 has 4 divisors (see below), whose sum is σ = 14641705853208. Its totient is φ = 9761137235464.
The previous prime is 12201421544321. The next prime is 12201421544369. The reversal of 12201421544335 is 53344512410221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12201421544335 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12201421544294 and 12201421544303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1220142154429 + ... + 1220142154438.
It is an arithmetic number, because the mean of its divisors is an integer number (3660426463302).
Almost surely, 212201421544335 is an apocalyptic number.
12201421544335 is a deficient number, since it is larger than the sum of its proper divisors (2440284308873).
12201421544335 is an equidigital number, since it uses as much as digits as its factorization.
12201421544335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2440284308872.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 12201421544335 its reverse (53344512410221), we get a palindrome (65545933954556).
The spelling of 12201421544335 in words is "twelve trillion, two hundred one billion, four hundred twenty-one million, five hundred forty-four thousand, three hundred thirty-five".
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