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122021012013000 = 233531719711773587
BaseRepresentation
bin11011101111101000111011…
…000100110111111111001000
3121000001002120010102202000020
4123233220323010313333020
5111443143013033404000
61111303402402140440
734462504266642312
oct3357507304677710
9530032503382006
10122021012013000
11359749032223a1
12118285a6051720
1353116bbc20a19
14221bbc439c7b2
15e190a7154ba0
hex6efa3b137fc8

122021012013000 has 512 divisors, whose sum is σ = 430292312985600. Its totient is φ = 28604395008000.

The previous prime is 122021012012989. The next prime is 122021012013007. The reversal of 122021012013000 is 310210120221.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is not an unprimeable number, because it can be changed into a prime (122021012013007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 67912207 + ... + 69685793.

It is an arithmetic number, because the mean of its divisors is an integer number (840414673800).

Almost surely, 2122021012013000 is an apocalyptic number.

122021012013000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 122021012013000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215146156492800).

122021012013000 is an abundant number, since it is smaller than the sum of its proper divisors (308271300972600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122021012013000 is a wasteful number, since it uses less digits than its factorization.

122021012013000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1773718 (or 1773704 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 122021012013000 its reverse (310210120221), we get a palindrome (122331222133221).

The spelling of 122021012013000 in words is "one hundred twenty-two trillion, twenty-one billion, twelve million, thirteen thousand".