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122024314113 = 3133128828567
BaseRepresentation
bin111000110100100110…
…1110100010100000001
3102122222002021102102020
41301221031310110001
53444401211022423
6132020204312053
711546606361552
oct1615115642401
9378862242366
10122024314113
11478285a9299
121b795842629
13b6786c5680
145c98130329
153292a6c4e3
hex1c69374501

122024314113 has 8 divisors (see below), whose sum is σ = 175214399808. Its totient is φ = 75091885584.

The previous prime is 122024314079. The next prime is 122024314129. The reversal of 122024314113 is 311413420221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 122024314113 - 230 = 120950572289 is a prime.

It is not an unprimeable number, because it can be changed into a prime (122024314133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1564414245 + ... + 1564414322.

It is an arithmetic number, because the mean of its divisors is an integer number (21901799976).

Almost surely, 2122024314113 is an apocalyptic number.

122024314113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

122024314113 is a deficient number, since it is larger than the sum of its proper divisors (53190085695).

122024314113 is a wasteful number, since it uses less digits than its factorization.

122024314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3128828583.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 122024314113 its reverse (311413420221), we get a palindrome (433437734334).

The spelling of 122024314113 in words is "one hundred twenty-two billion, twenty-four million, three hundred fourteen thousand, one hundred thirteen".

Divisors: 1 3 13 39 3128828567 9386485701 40674771371 122024314113