Base | Representation |
---|---|
bin | 1011000110010010110111… |
… | …0101001110010111001001 |
3 | 1121012120111002111221102020 |
4 | 2301210231311032113021 |
5 | 3044412233334440423 |
6 | 41541513044355053 |
7 | 2366423020134540 |
oct | 261445565162711 |
9 | 47176432457366 |
10 | 12202771015113 |
11 | 3985191126738 |
12 | 1450b8b3a5a89 |
13 | 6a6940b2b073 |
14 | 30288dadb157 |
15 | 16264e7a64e3 |
hex | b192dd4e5c9 |
12202771015113 has 32 divisors (see below), whose sum is σ = 18654253255680. Its totient is φ = 6950681167680.
The previous prime is 12202771015109. The next prime is 12202771015129. The reversal of 12202771015113 is 31151017720221.
It is not a de Polignac number, because 12202771015113 - 22 = 12202771015109 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12202771015153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 224573358 + ... + 224627688.
It is an arithmetic number, because the mean of its divisors is an integer number (582945414240).
Almost surely, 212202771015113 is an apocalyptic number.
It is an amenable number.
12202771015113 is a deficient number, since it is larger than the sum of its proper divisors (6451482240567).
12202771015113 is a wasteful number, since it uses less digits than its factorization.
12202771015113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88397.
The product of its (nonzero) digits is 5880, while the sum is 33.
Adding to 12202771015113 its reverse (31151017720221), we get a palindrome (43353788735334).
The spelling of 12202771015113 in words is "twelve trillion, two hundred two billion, seven hundred seventy-one million, fifteen thousand, one hundred thirteen".
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