122031120133 has 4 divisors (see below), whose sum is σ = 131418129388. Its totient is φ = 112644110880.

The previous prime is 122031120073. The next prime is 122031120137. The reversal of 122031120133 is 331021130221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10690112449 + 111341007684 = 103393^2 + 333678^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-122031120133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122031120133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122031120137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4693504608 + ... + 4693504633.

It is an arithmetic number, because the mean of its divisors is an integer number (32854532347).

Almost surely, 2^122031120133 is an apocalyptic number.

122031120133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

122031120133 is a deficient number, since it is larger than the sum of its proper divisors (9387009255).

122031120133 is an equidigital number, since it uses as much as digits as its factorization.

122031120133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9387009254.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 122031120133 its reverse (331021130221), we get a palindrome (453052250354).

It can be divided in two parts, 122031120 and 133, that added together give a triangular number (122031253 = T₁₅₆₂₂).

The spelling of 122031120133 in words is "one hundred twenty-two billion, thirty-one million, one hundred twenty thousand, one hundred thirty-three".