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12203215117128 = 23337279109257521
BaseRepresentation
bin1011000110010100100001…
…0011010101101101001000
31121012121122001011122212000
42301211020103111231020
53044414141032222003
641542025111151000
72366440022010600
oct261451023255510
947177561148760
1012203215117128
1139853998840a2
121451094075460
136a69b1b41319
143028d2aa1c00
1516267877c1a3
hexb19484d5b48

12203215117128 has 768 divisors, whose sum is σ = 40532088960000. Its totient is φ = 3391122309120.

The previous prime is 12203215117123. The next prime is 12203215117183. The reversal of 12203215117128 is 82171151230221.

12203215117128 is a `hidden beast` number, since 1 + 2 + 20 + 32 + 1 + 511 + 71 + 28 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 12203215117092 and 12203215117101.

It is not an unprimeable number, because it can be changed into a prime (12203215117123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 23422677508 + ... + 23422678028.

It is an arithmetic number, because the mean of its divisors is an integer number (52776157500).

Almost surely, 212203215117128 is an apocalyptic number.

12203215117128 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12203215117128, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20266044480000).

12203215117128 is an abundant number, since it is smaller than the sum of its proper divisors (28328873842872).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12203215117128 is a wasteful number, since it uses less digits than its factorization.

12203215117128 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 995 (or 978 counting only the distinct ones).

The product of its (nonzero) digits is 13440, while the sum is 36.

Adding to 12203215117128 its reverse (82171151230221), we get a palindrome (94374366347349).

The spelling of 12203215117128 in words is "twelve trillion, two hundred three billion, two hundred fifteen million, one hundred seventeen thousand, one hundred twenty-eight".