1220323400035 has 4 divisors (see below), whose sum is σ = 1464388080048. Its totient is φ = 976258720024.

The previous prime is 1220323400029. The next prime is 1220323400057. The reversal of 1220323400035 is 5300043230221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1220323400035 - 2¹¹ = 1220323397987 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1220323399982 and 1220323400009.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122032339999 + ... + 122032340008.

It is an arithmetic number, because the mean of its divisors is an integer number (366097020012).

Almost surely, 2^{1220323400035} is an apocalyptic number.

1220323400035 is a deficient number, since it is larger than the sum of its proper divisors (244064680013).

1220323400035 is an equidigital number, since it uses as much as digits as its factorization.

1220323400035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 244064680012.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 1220323400035 its reverse (5300043230221), we get a palindrome (6520366630256).

The spelling of 1220323400035 in words is "one trillion, two hundred twenty billion, three hundred twenty-three million, four hundred thousand, thirty-five".