Base | Representation |
---|---|
bin | 1011000110010111101000… |
… | …0100010000010000011101 |
3 | 1121012200210020012022000111 |
4 | 2301211322010100100131 |
5 | 3044422343301222303 |
6 | 41542244014130021 |
7 | 2366466510416041 |
oct | 261457204202035 |
9 | 47180706168014 |
10 | 12204050023453 |
11 | 3985788096622 |
12 | 14512877b0911 |
13 | 6a6ab5ac6432 |
14 | 302971916021 |
15 | 1626c6bebb6d |
hex | b197a11041d |
12204050023453 has 8 divisors (see below), whose sum is σ = 12846707383520. Its totient is φ = 11561426557200.
The previous prime is 12204050023423. The next prime is 12204050023469. The reversal of 12204050023453 is 35432005040221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12204050023453 - 25 = 12204050023421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12204050023423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7732698 + ... + 9176203.
It is an arithmetic number, because the mean of its divisors is an integer number (1605838422940).
Almost surely, 212204050023453 is an apocalyptic number.
It is an amenable number.
12204050023453 is a deficient number, since it is larger than the sum of its proper divisors (642657360067).
12204050023453 is a wasteful number, since it uses less digits than its factorization.
12204050023453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16946907.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 12204050023453 its reverse (35432005040221), we get a palindrome (47636055063674).
The spelling of 12204050023453 in words is "twelve trillion, two hundred four billion, fifty million, twenty-three thousand, four hundred fifty-three".
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