Base | Representation |
---|---|
bin | 1011000110011000101110… |
… | …0101101111010100010111 |
3 | 1121012201112201101120101002 |
4 | 2301212023211233110113 |
5 | 3044423444031422403 |
6 | 41542333115253515 |
7 | 2366510010326453 |
oct | 261461345572427 |
9 | 47181481346332 |
10 | 12204344014103 |
11 | 39859190360aa |
12 | 145134a14a29b |
13 | 6a6b3199bbb7 |
14 | 30299c9a3663 |
15 | 1626e2920188 |
hex | b198b96f517 |
12204344014103 has 4 divisors (see below), whose sum is σ = 12204613298640. Its totient is φ = 12204074729568.
The previous prime is 12204344014091. The next prime is 12204344014111. The reversal of 12204344014103 is 30141044340221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12204344014103 - 210 = 12204344013079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12204344014133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134574275 + ... + 134664932.
It is an arithmetic number, because the mean of its divisors is an integer number (3051153324660).
Almost surely, 212204344014103 is an apocalyptic number.
12204344014103 is a deficient number, since it is larger than the sum of its proper divisors (269284537).
12204344014103 is an equidigital number, since it uses as much as digits as its factorization.
12204344014103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 269284536.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 12204344014103 its reverse (30141044340221), we get a palindrome (42345388354324).
The spelling of 12204344014103 in words is "twelve trillion, two hundred four billion, three hundred forty-four million, fourteen thousand, one hundred three".
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