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1221000121113 = 3596898305769
BaseRepresentation
bin10001110001001001010…
…001110100101100011001
311022201121121010210110220
4101301021101310230121
5130001102012333423
62332530354030253
7154133343533643
oct21611121645431
94281547123426
101221000121113
11430906811993
1217877a578389
138b1a8242986
144314d58d893
1521b6365d9e3
hex11c49474b19

1221000121113 has 8 divisors (see below), whose sum is σ = 1655593384800. Its totient is φ = 800203469088.

The previous prime is 1221000121063. The next prime is 1221000121127. The reversal of 1221000121113 is 3111210001221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1221000121113 - 29 = 1221000120601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1221000121092 and 1221000121101.

It is not an unprimeable number, because it can be changed into a prime (1221000120113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3449152708 + ... + 3449153061.

It is an arithmetic number, because the mean of its divisors is an integer number (206949173100).

Almost surely, 21221000121113 is an apocalyptic number.

It is an amenable number.

1221000121113 is a deficient number, since it is larger than the sum of its proper divisors (434593263687).

1221000121113 is an equidigital number, since it uses as much as digits as its factorization.

1221000121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6898305831.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1221000121113 its reverse (3111210001221), we get a palindrome (4332210122334).

The spelling of 1221000121113 in words is "one trillion, two hundred twenty-one billion, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 59 177 6898305769 20694917307 407000040371 1221000121113