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122100211132031 = 1111879351321983
BaseRepresentation
bin11011110000110010101011…
…101101100010011001111111
3121000022122222122112211212002
4123300302223231202121333
5112000442213022211111
61111404021310132515
734501310025231056
oct3360625355423177
9530278878484762
10122100211132031
11359a5455046780
121183ba097b113b
135319001154972
142221978a1d39d
15e1b19017563b
hex6f0cabb6267f

122100211132031 has 8 divisors (see below), whose sum is σ = 133312446203904. Its totient is φ = 110906678706520.

The previous prime is 122100211131991. The next prime is 122100211132033. The reversal of 122100211132031 is 130231112001221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122100211132031 is a prime.

It is a super-3 number, since 3×1221002111320313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 122100211131994 and 122100211132012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122100211132033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4675647935 + ... + 4675674048.

It is an arithmetic number, because the mean of its divisors is an integer number (16664055775488).

Almost surely, 2122100211132031 is an apocalyptic number.

122100211132031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

122100211132031 is a deficient number, since it is larger than the sum of its proper divisors (11212235071873).

122100211132031 is a wasteful number, since it uses less digits than its factorization.

122100211132031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9351323181.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 122100211132031 its reverse (130231112001221), we get a palindrome (252331323133252).

The spelling of 122100211132031 in words is "one hundred twenty-two trillion, one hundred billion, two hundred eleven million, one hundred thirty-two thousand, thirty-one".

Divisors: 1 11 1187 13057 9351321983 102864541813 11100019193821 122100211132031