Base | Representation |
---|---|
bin | 111000110110111000… |
… | …0011111110101000001 |
3 | 102200011101122210011110 |
4 | 1301231300133311001 |
5 | 4000030212422423 |
6 | 132031525433533 |
7 | 11551523150154 |
oct | 1615560376501 |
9 | 380141583143 |
10 | 122100514113 |
11 | 478676144a6 |
12 | 1b7b726b8a9 |
13 | b68b425226 |
14 | 5ca42c7c9b |
15 | 32995c0193 |
hex | 1c6dc1fd41 |
122100514113 has 8 divisors (see below), whose sum is σ = 166264530048. Its totient is φ = 79668420464.
The previous prime is 122100514061. The next prime is 122100514147. The reversal of 122100514113 is 311415001221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 122100514113 - 222 = 122096319809 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 122100514113.
It is not an unprimeable number, because it can be changed into a prime (122100514313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 432980406 + ... + 432980687.
It is an arithmetic number, because the mean of its divisors is an integer number (20783066256).
Almost surely, 2122100514113 is an apocalyptic number.
It is an amenable number.
122100514113 is a deficient number, since it is larger than the sum of its proper divisors (44164015935).
122100514113 is an equidigital number, since it uses as much as digits as its factorization.
122100514113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 865961143.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 122100514113 its reverse (311415001221), we get a palindrome (433515515334).
The spelling of 122100514113 in words is "one hundred twenty-two billion, one hundred million, five hundred fourteen thousand, one hundred thirteen".
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