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122100514113 = 347865961093
BaseRepresentation
bin111000110110111000…
…0011111110101000001
3102200011101122210011110
41301231300133311001
54000030212422423
6132031525433533
711551523150154
oct1615560376501
9380141583143
10122100514113
11478676144a6
121b7b726b8a9
13b68b425226
145ca42c7c9b
1532995c0193
hex1c6dc1fd41

122100514113 has 8 divisors (see below), whose sum is σ = 166264530048. Its totient is φ = 79668420464.

The previous prime is 122100514061. The next prime is 122100514147. The reversal of 122100514113 is 311415001221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 122100514113 - 222 = 122096319809 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122100514113.

It is not an unprimeable number, because it can be changed into a prime (122100514313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 432980406 + ... + 432980687.

It is an arithmetic number, because the mean of its divisors is an integer number (20783066256).

Almost surely, 2122100514113 is an apocalyptic number.

It is an amenable number.

122100514113 is a deficient number, since it is larger than the sum of its proper divisors (44164015935).

122100514113 is an equidigital number, since it uses as much as digits as its factorization.

122100514113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 865961143.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 122100514113 its reverse (311415001221), we get a palindrome (433515515334).

The spelling of 122100514113 in words is "one hundred twenty-two billion, one hundred million, five hundred fourteen thousand, one hundred thirteen".

Divisors: 1 3 47 141 865961093 2597883279 40700171371 122100514113