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1221021112113 = 321112333546587
BaseRepresentation
bin10001110001001010100…
…001111001011100110001
311022201200001122020201100
4101301022201321130301
5130001122401041423
62332532423555013
7154134020131125
oct21611241713461
94281601566640
101221021112113
11430917649820
121787855bba69
138b1ac6b219a
1443152295585
1521b65408343
hex11c4a879731

1221021112113 has 12 divisors (see below), whose sum is σ = 1924033267728. Its totient is φ = 740012795160.

The previous prime is 1221021112081. The next prime is 1221021112147. The reversal of 1221021112113 is 3112111201221.

It is a happy number.

It is not a de Polignac number, because 1221021112113 - 25 = 1221021112081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1221021112183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6166773195 + ... + 6166773392.

It is an arithmetic number, because the mean of its divisors is an integer number (160336105644).

Almost surely, 21221021112113 is an apocalyptic number.

It is an amenable number.

1221021112113 is a deficient number, since it is larger than the sum of its proper divisors (703012155615).

1221021112113 is a wasteful number, since it uses less digits than its factorization.

1221021112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12333546604 (or 12333546601 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 1221021112113 its reverse (3112111201221), we get a palindrome (4333132313334).

The spelling of 1221021112113 in words is "one trillion, two hundred twenty-one billion, twenty-one million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 9 11 33 99 12333546587 37000639761 111001919283 135669012457 407007037371 1221021112113