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12210213133 = 31393877843
BaseRepresentation
bin10110101111100100…
…10001000100001101
31011111221200002120001
423113302101010031
5200001303310013
65335335124301
7611403046006
oct132762210415
934457602501
1012210213133
1151a638a938
122449213691
1311c78866b1
1483b8dc1ad
154b6e45ddd
hex2d7c9110d

12210213133 has 4 divisors (see below), whose sum is σ = 12604091008. Its totient is φ = 11816335260.

The previous prime is 12210213131. The next prime is 12210213139. The reversal of 12210213133 is 33131201221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12210213133 - 21 = 12210213131 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12210213133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12210213131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196938891 + ... + 196938952.

It is an arithmetic number, because the mean of its divisors is an integer number (3151022752).

Almost surely, 212210213133 is an apocalyptic number.

It is an amenable number.

12210213133 is a deficient number, since it is larger than the sum of its proper divisors (393877875).

12210213133 is an equidigital number, since it uses as much as digits as its factorization.

12210213133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 393877874.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12210213133 its reverse (33131201221), we get a palindrome (45341414354).

The spelling of 12210213133 in words is "twelve billion, two hundred ten million, two hundred thirteen thousand, one hundred thirty-three".

Divisors: 1 31 393877843 12210213133