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12211303130122 = 26105651565061
BaseRepresentation
bin1011000110110010101001…
…1000101010010000001010
31121020101111201012021212211
42301230222120222100022
53100032222100130442
641545443433255334
72400144321666445
oct261545230522012
947211451167784
1012211303130122
11398886a2a5a58
12145277086454a
136a76a068bb25
1430305cd1a65c
1516299d860617
hexb1b2a62a40a

12211303130122 has 4 divisors (see below), whose sum is σ = 18316954695186. Its totient is φ = 6105651565060.

The previous prime is 12211303130119. The next prime is 12211303130123. The reversal of 12211303130122 is 22103130311221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10333145259441 + 1878157870681 = 3214521^2 + 1370459^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12211303130093 and 12211303130102.

It is not an unprimeable number, because it can be changed into a prime (12211303130123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3052825782529 + ... + 3052825782532.

Almost surely, 212211303130122 is an apocalyptic number.

12211303130122 is a deficient number, since it is larger than the sum of its proper divisors (6105651565064).

12211303130122 is an equidigital number, since it uses as much as digits as its factorization.

12211303130122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6105651565063.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 12211303130122 its reverse (22103130311221), we get a palindrome (34314433441343).

The spelling of 12211303130122 in words is "twelve trillion, two hundred eleven billion, three hundred three million, one hundred thirty thousand, one hundred twenty-two".

Divisors: 1 2 6105651565061 12211303130122