Base | Representation |
---|---|
bin | 11011110000111110101100… |
… | …100111000011110110100010 |
3 | 121000100220021200010210011112 |
4 | 123300332230213003312202 |
5 | 112001200122421104442 |
6 | 1111413553325343322 |
7 | 34502244505244303 |
oct | 3360765447036642 |
9 | 530326250123145 |
10 | 122113111113122 |
11 | 359aa974817478 |
12 | 11842409a07b42 |
13 | 531a2a88a737c |
14 | 222243dd907aa |
15 | e1b69791c082 |
hex | 6f0fac9c3da2 |
122113111113122 has 4 divisors (see below), whose sum is σ = 183169666669686. Its totient is φ = 61056555556560.
The previous prime is 122113111113107. The next prime is 122113111113127. The reversal of 122113111113122 is 221311111311221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 116148276938521 + 5964834174601 = 10777211^2 + 2442301^2 .
It is a super-2 number, since 2×1221131111131222 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (122113111113127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30528277778279 + ... + 30528277778282.
Almost surely, 2122113111113122 is an apocalyptic number.
122113111113122 is a deficient number, since it is larger than the sum of its proper divisors (61056555556564).
122113111113122 is an equidigital number, since it uses as much as digits as its factorization.
122113111113122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61056555556563.
The product of its digits is 144, while the sum is 23.
Adding to 122113111113122 its reverse (221311111311221), we get a palindrome (343424222424343).
The spelling of 122113111113122 in words is "one hundred twenty-two trillion, one hundred thirteen billion, one hundred eleven million, one hundred thirteen thousand, one hundred twenty-two".
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