12211330103433 has 24 divisors (see below), whose sum is σ = 17731399196160. Its totient is φ = 8098052991840.

The previous prime is 12211330103419. The next prime is 12211330103437. The reversal of 12211330103433 is 33430103311221.

12211330103433 is a `hidden beast` number, since 1 + 2 + 2 + 1 + 13 + 301 + 0 + 343 + 3 = 666.

It is not a de Polignac number, because 12211330103433 - 2⁹ = 12211330102921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12211330103397 and 12211330103406.

It is not an unprimeable number, because it can be changed into a prime (12211330103437) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 92999335 + ... + 93130547.

It is an arithmetic number, because the mean of its divisors is an integer number (738808299840).

Almost surely, 2^{12211330103433} is an apocalyptic number.

It is an amenable number.

12211330103433 is a deficient number, since it is larger than the sum of its proper divisors (5520069092727).

12211330103433 is a wasteful number, since it uses less digits than its factorization.

12211330103433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185549 (or 185546 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 12211330103433 its reverse (33430103311221), we get a palindrome (45641433414654).

The spelling of 12211330103433 in words is "twelve trillion, two hundred eleven billion, three hundred thirty million, one hundred three thousand, four hundred thirty-three".