Base | Representation |
---|---|
bin | 111000110111010000… |
… | …1011100001110010011 |
3 | 102200012021210122000101 |
4 | 1301232201130032103 |
5 | 4000042004010103 |
6 | 132033104433231 |
7 | 11552040205231 |
oct | 1615641341623 |
9 | 380167718011 |
10 | 122113344403 |
11 | 47873888046 |
12 | 1b7bb618817 |
13 | b690c9810b |
14 | 5ca5ca7951 |
15 | 329a7a6a1d |
hex | 1c6e85c393 |
122113344403 has 4 divisors (see below), whose sum is σ = 122932897200. Its totient is φ = 121293791608.
The previous prime is 122113344401. The next prime is 122113344427. The reversal of 122113344403 is 304443311221.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 122113344403 - 21 = 122113344401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122113344401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 409776175 + ... + 409776472.
It is an arithmetic number, because the mean of its divisors is an integer number (30733224300).
Almost surely, 2122113344403 is an apocalyptic number.
122113344403 is a deficient number, since it is larger than the sum of its proper divisors (819552797).
122113344403 is an equidigital number, since it uses as much as digits as its factorization.
122113344403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 819552796.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 122113344403 its reverse (304443311221), we get a palindrome (426556655624).
The spelling of 122113344403 in words is "one hundred twenty-two billion, one hundred thirteen million, three hundred forty-four thousand, four hundred three".
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