Base | Representation |
---|---|
bin | 10001110001010101110… |
… | …010110101000101000011 |
3 | 11022202011020020211102000 |
4 | 101301111302311011003 |
5 | 130002014241200120 |
6 | 2333003254355043 |
7 | 154141503402252 |
oct | 21612562650503 |
9 | 4282136224360 |
10 | 1221210100035 |
11 | 430a042a0192 |
12 | 17881895ba83 |
13 | 8b20c8b2063 |
14 | 4316d40c799 |
15 | 21b76cd9990 |
hex | 11c55cb5143 |
1221210100035 has 64 divisors (see below), whose sum is σ = 2195917516800. Its totient is φ = 643874351616.
The previous prime is 1221210100027. The next prime is 1221210100057. The reversal of 1221210100035 is 5300010121221.
It is not a de Polignac number, because 1221210100035 - 23 = 1221210100027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1221210099990 and 1221210100017.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6830907 + ... + 7007403.
It is an arithmetic number, because the mean of its divisors is an integer number (34311211200).
Almost surely, 21221210100035 is an apocalyptic number.
1221210100035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1221210100035 is a deficient number, since it is larger than the sum of its proper divisors (974707416765).
1221210100035 is a wasteful number, since it uses less digits than its factorization.
1221210100035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 177097 (or 177091 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
Adding to 1221210100035 its reverse (5300010121221), we get a palindrome (6521220221256).
The spelling of 1221210100035 in words is "one trillion, two hundred twenty-one billion, two hundred ten million, one hundred thousand, thirty-five".
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