Base | Representation |
---|---|
bin | 10110101111110010… |
… | …11110000000001011 |
3 | 1011112002020000101220 |
4 | 23113321132000023 |
5 | 200002244214011 |
6 | 5335443413123 |
7 | 611425101246 |
oct | 132771360013 |
9 | 34462200356 |
10 | 12212101131 |
11 | 51a745a36a |
12 | 24499841a3 |
13 | 11c8097b59 |
14 | 83bc7025d |
15 | 4b71ba506 |
hex | 2d7e5e00b |
12212101131 has 4 divisors (see below), whose sum is σ = 16282801512. Its totient is φ = 8141400752.
The previous prime is 12212101127. The next prime is 12212101141. The reversal of 12212101131 is 13110121221.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13110121221 = 3 ⋅4370040407.
It is a cyclic number.
It is not a de Polignac number, because 12212101131 - 22 = 12212101127 is a prime.
It is a super-2 number, since 2×122121011312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12212101131.
It is not an unprimeable number, because it can be changed into a prime (12212101141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2035350186 + ... + 2035350191.
It is an arithmetic number, because the mean of its divisors is an integer number (4070700378).
Almost surely, 212212101131 is an apocalyptic number.
12212101131 is a deficient number, since it is larger than the sum of its proper divisors (4070700381).
12212101131 is an equidigital number, since it uses as much as digits as its factorization.
12212101131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4070700380.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 12212101131 its reverse (13110121221), we get a palindrome (25322222352).
The spelling of 12212101131 in words is "twelve billion, two hundred twelve million, one hundred one thousand, one hundred thirty-one".
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