Base | Representation |
---|---|
bin | 1011000110110110110111… |
… | …0010101101010110100011 |
3 | 1121020111102112012001122212 |
4 | 2301231231302231112203 |
5 | 3100042031103011120 |
6 | 41550151552352335 |
7 | 2400214333335536 |
oct | 261555562552643 |
9 | 47214375161585 |
10 | 12212434032035 |
11 | 398929a6a7336 |
12 | 1452a275456ab |
13 | 6a7820a6c163 |
14 | 3031291c0a1d |
15 | 162a17c9c6c5 |
hex | b1b6dcad5a3 |
12212434032035 has 8 divisors (see below), whose sum is σ = 14706705012720. Its totient is φ = 9735424442784.
The previous prime is 12212434031989. The next prime is 12212434032089. The reversal of 12212434032035 is 53023043421221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12212434032035 - 214 = 12212434015651 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12212434031992 and 12212434032010.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4315346300 + ... + 4315349129.
It is an arithmetic number, because the mean of its divisors is an integer number (1838338126590).
Almost surely, 212212434032035 is an apocalyptic number.
12212434032035 is a deficient number, since it is larger than the sum of its proper divisors (2494270980685).
12212434032035 is an equidigital number, since it uses as much as digits as its factorization.
12212434032035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8630695717.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 12212434032035 its reverse (53023043421221), we get a palindrome (65235477453256).
The spelling of 12212434032035 in words is "twelve trillion, two hundred twelve billion, four hundred thirty-four million, thirty-two thousand, thirty-five".
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