Base | Representation |
---|---|
bin | 10110101111110101… |
… | …10000110001000011 |
3 | 1011112002212020102110 |
4 | 23113322300301003 |
5 | 200002341041011 |
6 | 5335454550403 |
7 | 611431012503 |
oct | 132772606103 |
9 | 34462766373 |
10 | 12212440131 |
11 | 51a7671031 |
12 | 2449b08403 |
13 | 11c8186248 |
14 | 83bd1ba03 |
15 | 4b7235ba6 |
hex | 2d7eb0c43 |
12212440131 has 8 divisors (see below), whose sum is σ = 16303946944. Its totient is φ = 8131280040.
The previous prime is 12212440117. The next prime is 12212440169. The reversal of 12212440131 is 13104421221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12212440131 - 213 = 12212431939 is a prime.
It is a super-2 number, since 2×122124401312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12212440098 and 12212440107.
It is not an unprimeable number, because it can be changed into a prime (12212440231) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2583925 + ... + 2588646.
It is an arithmetic number, because the mean of its divisors is an integer number (2037993368).
Almost surely, 212212440131 is an apocalyptic number.
12212440131 is a deficient number, since it is larger than the sum of its proper divisors (4091506813).
12212440131 is an equidigital number, since it uses as much as digits as its factorization.
12212440131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5173361.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 12212440131 its reverse (13104421221), we get a palindrome (25316861352).
The spelling of 12212440131 in words is "twelve billion, two hundred twelve million, four hundred forty thousand, one hundred thirty-one".
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