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13104421221 = 34368140407
BaseRepresentation
bin11000011010001010…
…11001100101100101
31020211021021120110010
430031011121211211
5203314212434341
610004201120433
7642511512453
oct141505314545
936737246403
1013104421221
115615116691
122658789119
13130ac029c8
148c458b9d3
1551a6cb716
hex30d159965

13104421221 has 4 divisors (see below), whose sum is σ = 17472561632. Its totient is φ = 8736280812.

The previous prime is 13104421193. The next prime is 13104421301. The reversal of 13104421221 is 12212440131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13104421221 - 211 = 13104419173 is a prime.

It is a super-3 number, since 3×131044212213 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104421021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2184070201 + ... + 2184070206.

It is an arithmetic number, because the mean of its divisors is an integer number (4368140408).

Almost surely, 213104421221 is an apocalyptic number.

It is an amenable number.

13104421221 is a deficient number, since it is larger than the sum of its proper divisors (4368140411).

13104421221 is an equidigital number, since it uses as much as digits as its factorization.

13104421221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4368140410.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 13104421221 its reverse (12212440131), we get a palindrome (25316861352).

The spelling of 13104421221 in words is "thirteen billion, one hundred four million, four hundred twenty-one thousand, two hundred twenty-one".

Divisors: 1 3 4368140407 13104421221