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122130001113 = 3149379720901
BaseRepresentation
bin111000110111110000…
…0111110110011011001
3102200020110010212201120
41301233200332303121
54000110240013423
6132034501435453
711552331611121
oct1615740766331
9380213125646
10122130001113
114788222451a
121b80510bb89
13b69457a863
145ca81a1c81
15329be96ee3
hex1c6f83ecd9

122130001113 has 16 divisors (see below), whose sum is σ = 164365656000. Its totient is φ = 80660059200.

The previous prime is 122130001109. The next prime is 122130001129. The reversal of 122130001113 is 311100031221.

It is a happy number.

It is not a de Polignac number, because 122130001113 - 22 = 122130001109 is a prime.

It is a super-2 number, since 2×1221300011132 (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 122130001092 and 122130001101.

It is not an unprimeable number, because it can be changed into a prime (122130001013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 191038 + ... + 529863.

It is an arithmetic number, because the mean of its divisors is an integer number (10272853500).

Almost surely, 2122130001113 is an apocalyptic number.

It is an amenable number.

122130001113 is a deficient number, since it is larger than the sum of its proper divisors (42235654887).

122130001113 is a wasteful number, since it uses less digits than its factorization.

122130001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 721432.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 122130001113 its reverse (311100031221), we get a palindrome (433230032334).

The spelling of 122130001113 in words is "one hundred twenty-two billion, one hundred thirty million, one thousand, one hundred thirteen".

Divisors: 1 3 149 379 447 1137 56471 169413 720901 2162703 107414249 273221479 322242747 819664437 40710000371 122130001113