Base | Representation |
---|---|
bin | 111000110111110000… |
… | …0111110110011011001 |
3 | 102200020110010212201120 |
4 | 1301233200332303121 |
5 | 4000110240013423 |
6 | 132034501435453 |
7 | 11552331611121 |
oct | 1615740766331 |
9 | 380213125646 |
10 | 122130001113 |
11 | 4788222451a |
12 | 1b80510bb89 |
13 | b69457a863 |
14 | 5ca81a1c81 |
15 | 329be96ee3 |
hex | 1c6f83ecd9 |
122130001113 has 16 divisors (see below), whose sum is σ = 164365656000. Its totient is φ = 80660059200.
The previous prime is 122130001109. The next prime is 122130001129. The reversal of 122130001113 is 311100031221.
It is a happy number.
It is not a de Polignac number, because 122130001113 - 22 = 122130001109 is a prime.
It is a super-2 number, since 2×1221300011132 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 122130001092 and 122130001101.
It is not an unprimeable number, because it can be changed into a prime (122130001013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 191038 + ... + 529863.
It is an arithmetic number, because the mean of its divisors is an integer number (10272853500).
Almost surely, 2122130001113 is an apocalyptic number.
It is an amenable number.
122130001113 is a deficient number, since it is larger than the sum of its proper divisors (42235654887).
122130001113 is a wasteful number, since it uses less digits than its factorization.
122130001113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 721432.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 122130001113 its reverse (311100031221), we get a palindrome (433230032334).
The spelling of 122130001113 in words is "one hundred twenty-two billion, one hundred thirty million, one thousand, one hundred thirteen".
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