Base | Representation |
---|---|
bin | 10110101111111001… |
… | …11100001101100111 |
3 | 1011112010221020220222 |
4 | 23113330330031213 |
5 | 200003012330203 |
6 | 5335515114555 |
7 | 611435611643 |
oct | 132774741547 |
9 | 34463836828 |
10 | 12213011303 |
11 | 51a7a21179 |
12 | 244a142a5b |
13 | 11c832620c |
14 | 83c029c23 |
15 | 4b72ea038 |
hex | 2d7f3c367 |
12213011303 has 4 divisors (see below), whose sum is σ = 12222400008. Its totient is φ = 12203622600.
The previous prime is 12213011299. The next prime is 12213011323. The reversal of 12213011303 is 30311031221.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30311031221 = 27953 ⋅1084357.
It is a cyclic number.
It is not a de Polignac number, because 12213011303 - 22 = 12213011299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12213011323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4692401 + ... + 4695002.
It is an arithmetic number, because the mean of its divisors is an integer number (3055600002).
Almost surely, 212213011303 is an apocalyptic number.
12213011303 is a deficient number, since it is larger than the sum of its proper divisors (9388705).
12213011303 is an equidigital number, since it uses as much as digits as its factorization.
12213011303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9388704.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 12213011303 its reverse (30311031221), we get a palindrome (42524042524).
The spelling of 12213011303 in words is "twelve billion, two hundred thirteen million, eleven thousand, three hundred three".
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