Search a number
-
+
12213100121 = 49124873931
BaseRepresentation
bin10110101111111010…
…10001111001011001
31011112011002202202112
423113331101321121
5200003023200441
65335521042105
7611436431615
oct132775217131
934464082675
1012213100121
1151a7a81982
12244a186335
1311c8357781
1483c050345
154b73164eb
hex2d7f51e59

12213100121 has 4 divisors (see below), whose sum is σ = 12237974544. Its totient is φ = 12188225700.

The previous prime is 12213100091. The next prime is 12213100147. The reversal of 12213100121 is 12100131221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12213100121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12213100096 and 12213100105.

It is not an unprimeable number, because it can be changed into a prime (12213100021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12436475 + ... + 12437456.

It is an arithmetic number, because the mean of its divisors is an integer number (3059493636).

Almost surely, 212213100121 is an apocalyptic number.

It is an amenable number.

12213100121 is a deficient number, since it is larger than the sum of its proper divisors (24874423).

12213100121 is an equidigital number, since it uses as much as digits as its factorization.

12213100121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24874422.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 12213100121 its reverse (12100131221), we get a palindrome (24313231342).

The spelling of 12213100121 in words is "twelve billion, two hundred thirteen million, one hundred thousand, one hundred twenty-one".

Divisors: 1 491 24873931 12213100121