Base | Representation |
---|---|
bin | 1011000110111001011101… |
… | …1001101010100111011111 |
3 | 1121020120020011202010000112 |
4 | 2301232113121222213133 |
5 | 3100044443310012203 |
6 | 41550345130520235 |
7 | 2400240541034255 |
oct | 261562731524737 |
9 | 47216204663015 |
10 | 12213132110303 |
11 | 3989618753923 |
12 | 1452ba129607b |
13 | 6a7902587917 |
14 | 303193bb85d5 |
15 | 162a591e06d8 |
hex | b1b9766a9df |
12213132110303 has 4 divisors (see below), whose sum is σ = 12511013381328. Its totient is φ = 11915250839280.
The previous prime is 12213132110297. The next prime is 12213132110323. The reversal of 12213132110303 is 30301123131221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12213132110303 - 24 = 12213132110287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12213132110323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148940635451 + ... + 148940635532.
It is an arithmetic number, because the mean of its divisors is an integer number (3127753345332).
Almost surely, 212213132110303 is an apocalyptic number.
12213132110303 is a deficient number, since it is larger than the sum of its proper divisors (297881271025).
12213132110303 is an equidigital number, since it uses as much as digits as its factorization.
12213132110303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 297881271024.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12213132110303 its reverse (30301123131221), we get a palindrome (42514255241524).
The spelling of 12213132110303 in words is "twelve trillion, two hundred thirteen billion, one hundred thirty-two million, one hundred ten thousand, three hundred three".
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