122132441113 has 4 divisors (see below), whose sum is σ = 122134607568. Its totient is φ = 122130274660.

The previous prime is 122132441089. The next prime is 122132441143. The reversal of 122132441113 is 311144231221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311144231221 = 18143 ⋅17149547.

It is a cyclic number.

It is not a de Polignac number, because 122132441113 - 2²¹ = 122130343961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (122132441143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 996343 + ... + 1112188.

It is an arithmetic number, because the mean of its divisors is an integer number (30533651892).

Almost surely, 2^122132441113 is an apocalyptic number.

It is an amenable number.

122132441113 is a deficient number, since it is larger than the sum of its proper divisors (2166455).

122132441113 is an equidigital number, since it uses as much as digits as its factorization.

122132441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2166454.

The product of its digits is 1152, while the sum is 25.

Adding to 122132441113 its reverse (311144231221), we get a palindrome (433276672334).

The spelling of 122132441113 in words is "one hundred twenty-two billion, one hundred thirty-two million, four hundred forty-one thousand, one hundred thirteen".