Base | Representation |
---|---|
bin | 1011000110111010001010… |
… | …0111101000111110111011 |
3 | 1121020120201021220022022021 |
4 | 2301232202213220332323 |
5 | 3100100340000314003 |
6 | 41550415532535311 |
7 | 2400245314566322 |
oct | 261564247507673 |
9 | 47216637808267 |
10 | 12213320323003 |
11 | 3989704a15908 |
12 | 1453034321537 |
13 | 6a7932575997 |
14 | 3031b0bad0b9 |
15 | 162a6a9bc2bd |
hex | b1ba29e8fbb |
12213320323003 has 4 divisors (see below), whose sum is σ = 12213327312648. Its totient is φ = 12213313333360.
The previous prime is 12213320322979. The next prime is 12213320323019. The reversal of 12213320323003 is 30032302331221.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 12213320323003 - 25 = 12213320322971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12213320321003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1715223 + ... + 5231503.
It is an arithmetic number, because the mean of its divisors is an integer number (3053331828162).
Almost surely, 212213320323003 is an apocalyptic number.
12213320323003 is a deficient number, since it is larger than the sum of its proper divisors (6989645).
12213320323003 is an equidigital number, since it uses as much as digits as its factorization.
12213320323003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6989644.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 12213320323003 its reverse (30032302331221), we get a palindrome (42245622654224).
The spelling of 12213320323003 in words is "twelve trillion, two hundred thirteen billion, three hundred twenty million, three hundred twenty-three thousand, three".
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