1221405014003 has 4 divisors (see below), whose sum is σ = 1221620930040. Its totient is φ = 1221189097968.

The previous prime is 1221405013987. The next prime is 1221405014057. The reversal of 1221405014003 is 3004105041221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1221405014003 - 2⁴ = 1221405013987 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1221405014003.

It is not an unprimeable number, because it can be changed into a prime (1221405014083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107949533 + ... + 107960846.

It is an arithmetic number, because the mean of its divisors is an integer number (305405232510).

Almost surely, 2^{1221405014003} is an apocalyptic number.

1221405014003 is a deficient number, since it is larger than the sum of its proper divisors (215916037).

1221405014003 is an equidigital number, since it uses as much as digits as its factorization.

1221405014003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215916036.

The product of its (nonzero) digits is 960, while the sum is 23.

The spelling of 1221405014003 in words is "one trillion, two hundred twenty-one billion, four hundred five million, fourteen thousand, three".