Base | Representation |
---|---|
bin | 10001110001100001011… |
… | …010010111100001000011 |
3 | 11022202122211000111012211 |
4 | 101301201122113201003 |
5 | 130002414140422313 |
6 | 2333034500202551 |
7 | 154146361214632 |
oct | 21614132274103 |
9 | 4282584014184 |
10 | 1221405014083 |
11 | 430aa4319a81 |
12 | 178872099457 |
13 | 8b2410a8407 |
14 | 4318b269519 |
15 | 21b88e8be3d |
hex | 11c61697843 |
1221405014083 has 2 divisors, whose sum is σ = 1221405014084. Its totient is φ = 1221405014082.
The previous prime is 1221405014057. The next prime is 1221405014111. The reversal of 1221405014083 is 3804105041221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1221405014083 - 233 = 1212815079491 is a prime.
It is not a weakly prime, because it can be changed into another prime (1221405084083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610702507041 + 610702507042.
It is an arithmetic number, because the mean of its divisors is an integer number (610702507042).
Almost surely, 21221405014083 is an apocalyptic number.
1221405014083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221405014083 is an equidigital number, since it uses as much as digits as its factorization.
1221405014083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
The spelling of 1221405014083 in words is "one trillion, two hundred twenty-one billion, four hundred five million, fourteen thousand, eighty-three".
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