12214241131333 has 4 divisors (see below), whose sum is σ = 12351479795820. Its totient is φ = 12077002466848.

The previous prime is 12214241131307. The next prime is 12214241131387. The reversal of 12214241131333 is 33313114241221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7823108308324 + 4391132823009 = 2796982^2 + 2095503^2 .

It is a cyclic number.

It is not a de Polignac number, because 12214241131333 - 2¹³ = 12214241123141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12214241131295 and 12214241131304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12214241131933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68619332110 + ... + 68619332287.

It is an arithmetic number, because the mean of its divisors is an integer number (3087869948955).

Almost surely, 2^{12214241131333} is an apocalyptic number.

It is an amenable number.

12214241131333 is a deficient number, since it is larger than the sum of its proper divisors (137238664487).

12214241131333 is an equidigital number, since it uses as much as digits as its factorization.

12214241131333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137238664486.

The product of its digits is 10368, while the sum is 31.

Adding to 12214241131333 its reverse (33313114241221), we get a palindrome (45527355372554).

The spelling of 12214241131333 in words is "twelve trillion, two hundred fourteen billion, two hundred forty-one million, one hundred thirty-one thousand, three hundred thirty-three".