Base | Representation |
---|---|
bin | 11011110001011010101010… |
… | …100110010011010101100001 |
3 | 121000110202210120210120010110 |
4 | 123301122222212103111201 |
5 | 112002143123341143131 |
6 | 1111435441310321533 |
7 | 34504356632551353 |
oct | 3361325246232541 |
9 | 530422716716113 |
10 | 122143142131041 |
11 | 35a11685516749 |
12 | 118481ab1b92a9 |
13 | 532008350c865 |
14 | 2223a8c5910d3 |
15 | e1c354121646 |
hex | 6f16aa993561 |
122143142131041 has 16 divisors (see below), whose sum is σ = 163899335106944. Its totient is φ = 80907883789824.
The previous prime is 122143142131037. The next prime is 122143142131051. The reversal of 122143142131041 is 140131241341221.
It is not a de Polignac number, because 122143142131041 - 22 = 122143142131037 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122143142131051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13686225 + ... + 20774961.
It is an arithmetic number, because the mean of its divisors is an integer number (10243708444184).
Almost surely, 2122143142131041 is an apocalyptic number.
It is an amenable number.
122143142131041 is a deficient number, since it is larger than the sum of its proper divisors (41756192975903).
122143142131041 is a wasteful number, since it uses less digits than its factorization.
122143142131041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7125480.
The product of its (nonzero) digits is 4608, while the sum is 30.
Adding to 122143142131041 its reverse (140131241341221), we get a palindrome (262274383472262).
The spelling of 122143142131041 in words is "one hundred twenty-two trillion, one hundred forty-three billion, one hundred forty-two million, one hundred thirty-one thousand, forty-one".
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