Base | Representation |
---|---|
bin | 11011110010010010100000… |
… | …010111011110000111001010 |
3 | 121000200111120011010112210022 |
4 | 123302102200113132013022 |
5 | 112004133422100404002 |
6 | 1111523155032020442 |
7 | 34511611511260061 |
oct | 3362224027360712 |
9 | 530614504115708 |
10 | 122203100013002 |
11 | 35a35053146908 |
12 | 11857942b31722 |
13 | 532591a311118 |
14 | 22269395dd1d8 |
15 | e1dbb2d04ba2 |
hex | 6f24a05de1ca |
122203100013002 has 4 divisors (see below), whose sum is σ = 183304650019506. Its totient is φ = 61101550006500.
The previous prime is 122203100012999. The next prime is 122203100013017. The reversal of 122203100013002 is 200310001302221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 71677033480441 + 50526066532561 = 8466229^2 + 7108169^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30550775003249 + ... + 30550775003252.
Almost surely, 2122203100013002 is an apocalyptic number.
122203100013002 is a deficient number, since it is larger than the sum of its proper divisors (61101550006504).
122203100013002 is an equidigital number, since it uses as much as digits as its factorization.
122203100013002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61101550006503.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 122203100013002 its reverse (200310001302221), we get a palindrome (322513101315223).
The spelling of 122203100013002 in words is "one hundred twenty-two trillion, two hundred three billion, one hundred million, thirteen thousand, two".
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