Base | Representation |
---|---|
bin | 1011000111010100001111… |
… | …0101101101101011000100 |
3 | 1121021020210010020101200200 |
4 | 2301311003311231223010 |
5 | 3100204203422030200 |
6 | 41553534302410500 |
7 | 2400613632034350 |
oct | 261650365555304 |
9 | 47236703211620 |
10 | 12220320111300 |
11 | 3991677135414 |
12 | 1454468590a30 |
13 | 6a84a9806452 |
14 | 3036766b2460 |
15 | 162d2a293800 |
hex | b1d43d6dac4 |
12220320111300 has 432 divisors, whose sum is σ = 46096306314240. Its totient is φ = 2645262385920.
The previous prime is 12220320111283. The next prime is 12220320111301. The reversal of 12220320111300 is 311102302221.
12220320111300 is a `hidden beast` number, since 1 + 2 + 220 + 32 + 0 + 111 + 300 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (12220320111301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 367103257 + ... + 367136543.
Almost surely, 212220320111300 is an apocalyptic number.
12220320111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12220320111300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23048153157120).
12220320111300 is an abundant number, since it is smaller than the sum of its proper divisors (33875986202940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12220320111300 is a wasteful number, since it uses less digits than its factorization.
12220320111300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36400 (or 36390 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 12220320111300 its reverse (311102302221), we get a palindrome (12531422413521).
The spelling of 12220320111300 in words is "twelve trillion, two hundred twenty billion, three hundred twenty million, one hundred eleven thousand, three hundred".
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