Base | Representation |
---|---|
bin | 1011000111010110110100… |
… | …1001010011010100110001 |
3 | 1121021022120102020111002110 |
4 | 2301311231021103110301 |
5 | 3100212113324041423 |
6 | 41554131140035533 |
7 | 2400640045325031 |
oct | 261655511232461 |
9 | 47238512214073 |
10 | 12221013112113 |
11 | 39919a2334163 |
12 | 1454620692ba9 |
13 | 6a858a264ac0 |
14 | 3037007478c1 |
15 | 162d6b032193 |
hex | b1d6d253531 |
12221013112113 has 64 divisors (see below), whose sum is σ = 19069350379520. Its totient is φ = 6894324460800.
The previous prime is 12221013112057. The next prime is 12221013112129. The reversal of 12221013112113 is 31121131012221.
12221013112113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12221013112113 - 213 = 12221013103921 is a prime.
It is a super-2 number, since 2×122210131121132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 12221013112113.
It is not an unprimeable number, because it can be changed into a prime (12221013112313) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 357940023 + ... + 357974163.
It is an arithmetic number, because the mean of its divisors is an integer number (297958599680).
Almost surely, 212221013112113 is an apocalyptic number.
12221013112113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12221013112113 is a deficient number, since it is larger than the sum of its proper divisors (6848337267407).
12221013112113 is a wasteful number, since it uses less digits than its factorization.
12221013112113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49790.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 12221013112113 its reverse (31121131012221), we get a palindrome (43342144124334).
The spelling of 12221013112113 in words is "twelve trillion, two hundred twenty-one billion, thirteen million, one hundred twelve thousand, one hundred thirteen".
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