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12221313000 = 23353131916493
BaseRepresentation
bin10110110000111001…
…00110111111101000
31011112201120000201020
423120130212333220
5200012124004000
65340413052440
7611566306101
oct133034467750
934481500636
1012221313000
115201681386
122450a87120
1311c9c71a70
1483d18b3a8
154b7dd9ba0
hex2d8726fe8

12221313000 has 256 divisors, whose sum is σ = 43227475200. Its totient is φ = 2849817600.

The previous prime is 12221312969. The next prime is 12221313007. The reversal of 12221313000 is 31312221.

It is a super-3 number, since 3×122213130003 (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is not an unprimeable number, because it can be changed into a prime (12221313007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 732754 + ... + 749246.

It is an arithmetic number, because the mean of its divisors is an integer number (168857325).

Almost surely, 212221313000 is an apocalyptic number.

12221313000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12221313000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21613737600).

12221313000 is an abundant number, since it is smaller than the sum of its proper divisors (31006162200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12221313000 is a wasteful number, since it uses less digits than its factorization.

12221313000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16549 (or 16535 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 12221313000 its reverse (31312221), we get a palindrome (12252625221).

It can be divided in two parts, 12221 and 313000, that added together give a triangular number (325221 = T806).

The spelling of 12221313000 in words is "twelve billion, two hundred twenty-one million, three hundred thirteen thousand".