Base | Representation |
---|---|
bin | 1011000111010111111110… |
… | …1111110111111011011011 |
3 | 1121021100101011111212120111 |
4 | 2301311333233313323123 |
5 | 3100213233223312103 |
6 | 41554222125305151 |
7 | 2400650555205235 |
oct | 261657757677333 |
9 | 47240334455514 |
10 | 12221325213403 |
11 | 3992042523509 |
12 | 14546a91051b7 |
13 | 6a8609b0ba17 |
14 | 30372dd8b255 |
15 | 162d8863186d |
hex | b1d7fbf7edb |
12221325213403 has 8 divisors (see below), whose sum is σ = 12397776062400. Its totient is φ = 12045418127808.
The previous prime is 12221325213379. The next prime is 12221325213407. The reversal of 12221325213403 is 30431252312221.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12221325213403 - 213 = 12221325205211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12221325213407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 135895576 + ... + 135985477.
It is an arithmetic number, because the mean of its divisors is an integer number (1549722007800).
Almost surely, 212221325213403 is an apocalyptic number.
12221325213403 is a deficient number, since it is larger than the sum of its proper divisors (176450848997).
12221325213403 is an equidigital number, since it uses as much as digits as its factorization.
12221325213403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 271881701.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 12221325213403 its reverse (30431252312221), we get a palindrome (42652577525624).
The spelling of 12221325213403 in words is "twelve trillion, two hundred twenty-one billion, three hundred twenty-five million, two hundred thirteen thousand, four hundred three".
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